Math, asked by celine17d, 5 months ago

18. Present ages of Rudy and Keith are in the ratio of
5:4 respectively. Three years hence, the ratio of
their ages will become 11:9 respectively. What is
Rudy's present age in years?​

Answers

Answered by Tsubhiksha
0

Step-by-step explanation:

Given, the present ages of Ritu and Sahil are in ratio 5:4.

Let the age of Ritu and Sahil are 5x and 4x years.

Then after 3 years age of Ritu and Sahil are 5x+3 and 4x+3.

Given age after 3 years are in ratio 11:9.

4x+3

5x+3

=

9

11

⇒45x+27=44x+33

⇒45x−44x=33−27

⇒x=6

Then age of present age of Sahil = 4×6=24 years

Answered by EhsaanGhaazi
0

Sahil's present age in years is 24.

Given that Ritu and Sahil are 5 years apart in age, the ratio is 5:4.

Let Ritu and Sahil be 5 and 4 years old, respectively.

After 3 years, Ritu and Sahil's ages are 5x+3 and 4x+3.

After three years, the ratio is 11:9.

∴   \frac{5x+3}{4x+3} = \frac{11}{9}

⇒ 45x + 27 = 44x + 33

⇒  45x-44x-33+27 = 0

⇒  x = 6

Thus the present age of Sahil is 4x6 = 24 years.

#SPJ3

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