Math, asked by kmluke6322, 1 year ago

18 prove that the quadrilateral formed by angle bisectors of a cyclic quadrilateral is also cyclic.

Answers

Answered by ABHINAVrAI
1

Given a quadrilateral ABCD with internal angle bisectors AF, BH, CH


and DF of angles A, B, C and D respectively and the points E, F, G


and H form a quadrilateral EFGH.



To prove that EFGH is a cyclic quadrilateral.



∠HEF = ∠AEB [Vertically opposite angles] -------- (1)


Consider triangle AEB,


∠AEB + ½ ∠A + ½ ∠ B = 180°


∠AEB  = 180° – ½ (∠A + ∠ B) -------- (2)



From (1) and (2),


∠HEF = 180° – ½ (∠A + ∠ B) --------- (3)



Similarly, ∠HGF = 180° – ½ (∠C + ∠ D) -------- (4)



From 3 and 4,


∠HEF + ∠HGF = 360° – ½ (∠A + ∠B + ∠C + ∠ D)


                         = 360° – ½ (360°)


                         = 360° – 180°


                         = 180°


So, EFGH is a cyclic quadrilateral since the sum of the opposite


angles of the quadrilateral is 180°.


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