Question

18. Reema had a long beaded string.she gave 2/5th of it to ritu and 3/4th of the remaining to
sudha. How much of the string is left with Reema?​

Answer 1

Answer:

Let the total string wit reema be 1

Now, she gave 2/5th of it to ritu

So, 1-2/5 of 1 =3/5

Now, she gave 3/4th of it to sudha

So, 3/4 - 3/4 of 3/5= 11/20

So,Reema is left with 11/20 of the total string.

Answer 2

Reema is left with $\frac{3x}{20}$ of the string

Solution:

Given that,

Reema had a long beaded string

Let the string with Reema be "x"

she gave 2/5th of it to ritu

Which means,

$Ritu = \frac{2}{5} \times x$

Therefore,

$Remaining = x - \frac{2}{5}x\\\\Remaining = \frac{5x-2x}{5}\\\\Remaining = \frac{3x}{5}$

3/4th of the remaining to  sudha

$Sudha = \frac{3}{4} \times \frac{3x}{5}\\\\Sudha = \frac{9x}{20}$

Therefore,

$Remaining = \frac{3x}{5} - \frac{9x}{20}\\\\Remaining = \frac{3x}{20}$

Thus she is left with $\frac{3x}{20}$ of the string

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