Question

(18) S [sin (log x) + cos (log x)]*dx =
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Answer 1

Answer:

sin(logx)+cos(logx)]dx

=∫sin(logx)dx+∫cos(logx)dx

Integrating by parts,

=xsin(logx)−∫cos(logx)dx+∫cos(logx)dx

=xsin(logx)+c

Step-by-step explanation:

g