Question

- 18
sec A- tan A cosec A -cot A
V sec A + tan A V cosec A + cot A
= (sec A – tan A) (cosec A - cot A).​

Answer 1

Answer:

Step-by-step explanation:

i(12 + 1). The equivalent in 2.2 was given correctly.

2.36 (A. Bager). The inequality may be generalized to

- .!.(n-2)

tan n a + tan n S + tan n 1. >.: 3 2 2 2 2 .

n being a natural number. It follows from 2.65.

2.41. The inequality may be generalized to

1 n ex S y 2(n+2)

cotan 2 + cotann 2 + cotann 2 ~ 3

for integer n.

v. G. Zvezdin, Matematika v ~kole 1968, 65.

2.41 is the case n = 1; for n = 2 we-have 2.43.

2.45 (A. Bager). This inequality is only valid for acute triangles. Same

remark holds for 2.47, the first inequality in 2.55 and 2.63.

I. Paasche, Praxis Math. 28 (1986),376 and 379

hope it helps

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