Question

18. Sheeba wants to paint the walls and ceiling of her dining hall whose length is 15 m, breadth is
12 m and height is 9 m. Ifone container of the paint can be used to paint 111 m’of area, then how
many containers of paint will be required to paint the whole room?​

Answer 1

Given:-

• Sheeba wants to paint the walls and ceiling of her dining hall whose

1. length is 15 m
2. breadth is 12 m
3. and height is 9 m.

To Find:-

• If one container of the paint can be used to paint 111m of area, then how many containers of paint will be required to paint the whole room?

Step by Step Explaination:-

• Total surface area of four walls

$\implies \sf{2(l+b) × h}$

• Area of ceiling:- lb

• Total area to be painted:-

$\implies \sf{ 2(l+b) × h + lb}$

$\implies \sf{2{[15 + 12]}9 + {[15 \times 12]}}$

$\implies \sf2 \times 27\times 9 + 180$

$\implies \sf486 + 180 = 666$

$\large\leadsto \sf666{m}^{2}$

• 1 can paints:- 111m²
• No. of cans required:-

$\implies \large\sf \frac{666}{111} = 6$

$\pink { \boxed{ \sf{Therefore, 6 \: cans \: are \: required \: to \: paint \: 666m²}}}$

Answer 2

Given:-

• Length of the room = 15 m
• Breadth = 12 m
• Height = 9 m
• 1 container can paint = 111 m² of area

To Find: No. of paint containers required to paint the four walls and the ceiling.

Area to be painted :

lb + bh + bh + lh + lh

= lb + 2bh + 2lh

= 2h(b + l) + lb

As per formula,

Area to be painted:-

2h(l + b) + lb

= 2 × 9(15 + 12) + (15)(12) m²

= 18 × 27 + 15 × 12 m²

= 486 + 180 m²

= 666 m²

Thus, area to be painted = 666 m²

NOW, finding containers required to paint:-

Here,

Total Area painted = (No. of containers)(Area painted by each container)

→ No. of containers = (Total area painted)/(Area painted by each container)

→ No. of containers = (666 m²)/(111 m²)

= 6 (Answer)

Final Answer:-

Six paint containers were required to paint the ceiling and the four walls.