Question

18. Show how you would connect three resistors, each of
resistance 10ohm, so that combination has a resistance
of a 15 b. 6.67​

Answer 1

Answer:

Explanation

Thera are 4 possibilities for this situation.

CASE:1

Connect them in series. then the net resistance would be 10+10+10=30ohm

SINCE It is not the required resistance that case is excluded

CASE:2

Connect them in parallel manner. then the net resistance wld be 1/10+1/10+1/10=1/R

R=10/3=3.33ohm

hence this case is also excluded.

CASE;3

Connect 2 resistors in series and 1 in parallel

then,10+10=20ohm

1/20+1/10=1/R

R=20/3=6.67ohm

HENCE CASE 3 IS THE ANSWER FOR (B).

CASE:4

Connect 2 resistors in parallel and 1 in series

1/10 +1/10 =1/Rp

Rp=100/20=5ohm

Rs+Rp=R

5+10=15ohm=R

HENCE CASE 4 IS THE ANSWER FOR A.