18. Solve the following systems by 'ELIMINATION BY EQUATING COEFFICIENTS' method and find 2x + y :
8x + 7y = 2xy ;
6x + y = 10xy
Standard:- 10
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Answered by
10
Hey friend ☺ here is the answer __________________________
2x + y = 2 × - 1/2 + 1/2 = - 1 + 1/2 = - 1/2 is the answer
And for the value of x and y plz see this attachment.
hope this helps you.
2x + y = 2 × - 1/2 + 1/2 = - 1 + 1/2 = - 1/2 is the answer
And for the value of x and y plz see this attachment.
hope this helps you.
Attachments:
Anonymous:
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Answered by
6
Given :
8x + 7y = 2xy --------- (1)
6x + y = 10xy --------- (2)
On solving (1) * 6 & (2) * 8, we get
= > 48x + 42y = 12xy
= > 48x + 8y = 80xy
-----------------------------
34y = -68xy
x = (-1/2).
Substitute x = -1/2 in (1), we get
= > 8x + 7y = 2xy
= > 8(-1/2) + 7y = 2xy
= > -4 + 7y = 2(-1/2)y
= > -4 + 7y = -y
= > 8y = 4
= > y = (1/2).
Then,
= > 2x + y
= > 2(-1/2) + (1/2)
= > -1 + (1/2)
= > (-2 + 1)/2
= > -1/2.
Hope this helps!
8x + 7y = 2xy --------- (1)
6x + y = 10xy --------- (2)
On solving (1) * 6 & (2) * 8, we get
= > 48x + 42y = 12xy
= > 48x + 8y = 80xy
-----------------------------
34y = -68xy
x = (-1/2).
Substitute x = -1/2 in (1), we get
= > 8x + 7y = 2xy
= > 8(-1/2) + 7y = 2xy
= > -4 + 7y = 2(-1/2)y
= > -4 + 7y = -y
= > 8y = 4
= > y = (1/2).
Then,
= > 2x + y
= > 2(-1/2) + (1/2)
= > -1 + (1/2)
= > (-2 + 1)/2
= > -1/2.
Hope this helps!
:-)
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