Question

18) Solve the x2+8x-48=0 by factorization method

12 and 4
-6 and 2
12 and 4
6 and 2​

Answer 1

${x}^{2} + 8x - 48 = 0 \\ {x}^{2} + 12x - 4x - 48 = 0 \\ x(x + 12) - 4(x + 12) = 0 \\ (x - 4)(x + 12) = 0 \\ x = 4 \: or \: x = - 12$

Final answer = -12 and 4