Question

18. The ages of Albert and Nelson are in the ratio 5 : 7. If 18 years ago, their ages were in the ratio 8:13, then find their present ages


solutions ​

Answer 1

Answer:

Let the present ages of two persons be 5x and 7x years Age of two persons 18 years ago are (5x – 18) and (7x – 18) years Given (5x – 18)/(7x – 18) = 8/13 13(5x – 18) = 8(7x – 18) 65x – 234 = 56x – 144 9x = 90 Therefore, x = 10 Thus age of the two persons are 50 and 70 years.

Step-by-step explanation:

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Answer 2

As per given in the question

we have the data

Let the present ages albert=5x

the present age of nelson =7x

age of two persons 18 year ago are  are

(5x – 18) and (7x – 18) years

(5x – 18)/(7x – 18) = 8/13

hence

13(5x – 18) = 8(7x – 18)

65x – 234 = 56x – 144

 9x = 90

Therefore, x = 10

Hence age of the two persons are 50 and 70 years.