Question

18. The base of an isosceles triangle is 12 cm and its perimeter is 32 cm. Find its area.

Answer 1

Answer:

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Answer 2

2 AB + 12 = 32

2AB = 32-12

2AB = 20

$= \frac{20}{2} AB = 10$

$S = \frac{32}{2} = 16$

$= \sqrt{s(s - a)(s - b)(s - c)}$

$= \sqrt{16(16 - 10)(16 - 10)(16 - 12)}$

$= \sqrt{16 \times 6 \times 6 \times 4}$

$= 4 \times 8 \times 2$

$= 48 \: {cm}^{2}$