Question

18. The brakes applied to a car produced an acceleration of 4 m/s in the opposite direction to the motion. If the car takes 3 s to stop after the application of brakes, calculate the distance it travels during the time.​

Answer 1

Step-by-step explanation:

Given:

Accerleration: a = −6 m/s²

Time t = 2 s

Final velocity, v = 0 m/s

v = u + at

0 = u − 6 × 2

u = 12 m/s

s = ut + ½ at²

s = 12 × 2 + ½ × (−6) × 4

⇒s = 12 m

Hope it helps you mate..