Physics, asked by drmrsbaig, 10 months ago


18. The current (1) flowing through a conductor depends on : (i) number density of electrons (n) (ii) charge on
the electron (e) (iii) area of cross-section (A) of the conductor and (iv) the drift velocity (Vd) of the
electron. Obtain a relation for I.
[I = neAvd]​

Answers

Answered by adithyassureshkumar
0

Answer:

Explanation:

consider a conductor having length L and A as area of cross section

let number of electrons in the conductor be N

when a potential difference of V is applied across the conductor

an electric field E sets across the conductor

E = V/L

due to the electric field electron experience a force F

F = E*e (e is the charge of electron)

F = ma

m a = E *e

a = E*e /m

the electron acclerates and collides with other electron and comes to stop...agiain acclerates and stops...this goes on and on until it travels the whole length of the conductor

v₁ =  u +a t₁ ..here u is zero so the velocity of electron just before first collision is given by this eqn

v₂ = a t₂ velocity of electron just before second collision is given by this eqn

it goes on like v₃ v₄ v₅....................vₙ

therefore average velocity = drift velocity = v₁ + v₂ + v₃+.............vₙ / n

Vdrift = at1+at2 +at3............atn / n

a (t₁ +t₂ +t₃................tₙ)/n

let (t₁ +t₂ +t₃................tₙ)/n = avaerge relaxation time =τ

Vdrift = aτ

=  (E e  / m ) *τ

time taken by one electron to cross the conductor length L

t = distance L / Vdrift

current I = q/t

total number of electron = N

total charge = Ne

charge density n = Ne / AL(volume of conductor)

total charge = n*AL

CURRENT =( N A L e ) / ( L / Vdrift )

current = NAe Vdrift

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