Physics, asked by snehithaprabhu22, 11 hours ago

18. The displacement of an sHm isy = 2. sin (2πt+π/3) The Time period is​

Answers

Answered by nusrathcassim
0

Answer:

y = 2sin(2πt + π/3) this equation is in form of

y = Asin(ωt + Ф)

y= displacement

A = amplitude

ω = angular velocity

t = time

Ф = initial phase

T = 1/f

f = ω/2π = 2π/2π = 1s^-1

T = 1 /1 = 1

Explanation:

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