Question

18. The equation of a line is 3x + 4y - 7 = 0. Find
(i) the slope of the line.
(ii) the equation of a line perpendicular to the given line and passing through the
intersection of the lines x – y + 2 = 0 and 3x + y - 10 = 0​

Answer 1

Answer:

3x + 4y – 7 = 0 .....(1)

1) Slope of the line m =

coefficient of x

coefficient of y

=

−

3

4

coefficient of xcoefficient of y=-34

2) Equation of line perpendicular to the given line

4x – 3y = λ ......(2)

Solving the equations x – y + 2 = 0 and 3x + y – 10 = 0, point of intersection is (2, 4).

Line (2) passes through points (2, 4).

4(2) – 3(4) = λ ⇒ λ = –4

Hence, the equation of required line is

4x - 3y + 4 = 0

Answer 2

Answer:

Step-by-step explanation:

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