Question

18. The floor of a room 5 m long and 6 m wide is to be covered by square tiles. If each square tile is 50 cm
long, then find the number of tiles required to cover the floor. Also, find the cost of tiling at the rate of
4.5 per tile.​

Answer 1

Answer:

120 tiles are required with the total cost of ₹540

Step-by-step explanation:

=》5m= 500cm

=》6m=600cm

=》Are of floor= (500*600)cm²

=》Area of 1 tile=(50*50)cm²

=》No. of tiles required= Area of floor/Area of a square tile

=500*600/50*50

=120 ans..

=》Cost of tilling= tiles required*raye of tile

=₹(120*4.5)

=₹540

Answer 2

Answer:

The floor of a room 5 m long and 6 m wide is to be covered by square tiles. If each square tile is 50 cm long, then the number of tiles required to cover the floor is 120, and the cost of tiling at the rate of 4.5 per tile is 540rupees.

Step-by-step explanation:

The length of the floor $l=5m=500cm$

the breadth of the floor $b=6m=600cm$

since the floor is a rectangle the total area of the floor is $A=l*b$

⇒ $A=500*600=300000cm^{2}$

the side of the square tile $a=50cm$

since the tile is a square the area of one tile $A=a^{2}$

⇒$A=50*50=2500cm^{2}$

now the number of tiles is given as the area of the floor divided by the area of one tile

⇒  $\frac{300000}{2500}=120$

the cost of one tile is $4.5rs/-$

now the total cost of the tile is the product of the total number of tiles and the price of one tile

⇒$120*4.5=540rs/-$