Question

18 The force acting on a particle makes an angle of
60° with the positive x - axis. If the magnitude of
the force is 10N What are its x and y
components?

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Answer 1

Answer:

A block of mass m= 2 kg is resting on a rough inclined plane of inclination 30

0

as shown in Fig. The coefficient of friction between the block and the plane is μ=0.5 What minimum force F ( in newton) should be applied perpendicular to the plane on the block, so that the block does not slip on the plane?

View Answer

Answer 2

Answer:

x component = 5N

y component = 5√3N

Step-by-step explanation:

Since the force is making an angle of 60° with +ve x-axis.

its x component will be Fcos60 and y component will be Fsin60

now F= 10N

cos60 = 1/2

sin60 =√3/2

x component = 10*1/2 = 5N

y component = 10*√3/2 = 5√3 N

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