Question

18 The formula of the phosphate of an element
is RPO4, then the formulae of its hydroxide a
sulphide, respectively, are and
(a) R(OH)3 and R3S
(b) R(OH)2 and RS;
(c) R(OH)2 and R3S2
(d) R(OH)3 and RS3 it is of chemistry






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Answer 1

Answer:

R(OH)₃ and R₂S₃

Explanation:

Since the formula is RPO₄, the valency of R is 3 since the charge of PO₄³⁻ ion is completely neutralised by the R³⁺ ion.

When combination with OH,

                                   R                         OH

                                    3                          1

Interchanging the valencies, R(OH)₃

When combination with S,

                                    R                          S

                                    3                           2

Interchanging the valencies, R₂S₃

Answer 2

Explanation:

$\bigstar \fcolorbox{blue}{red}{answer}$

Explanation:

To solve this kind of questions, we need to know the oxidation states of different ions.

So we consider the oxidation state of the ion ' R' to be x

And we should be knowing that the oxidation state of a phospate ion is 3-.

The compound is made up of 2 ions basically:

$R ^ x and PO^ {3-} _{4}$

Now arrange these numbers and variables to form an equation

$\rightarrow x + (- 3) = 0$

$\fcolorbox{red}{green}{x = 3}$

Therefore the oxidation state of ion ' R' is 3+

The formula of hydroxide of R will be:

Cross multiply the valencies.

${R = 3}$

$\red{OH = 1}$

$R(OH)_{3}$

$R = 3$

The formula of the sulfide of R will be as follows:

$R = 3$

$S = 2$

$R_{2} S_{3}$