Question

18) The HCF of two numbers is 6 and LCM is 72. If one number is 18, find its other number 19) Write down Pomar​

Answer 1

Answer: LCM*HCF=Product of two no.s

72*6=18*x

x=24.

Step-by-step explanation:

Answer 2

18) =)I will give you a simple method to do it.

(18)=)Always remember, LCM is always divisible by HCF.

=)So, divide LCM/HCF = 72/6 = 12

=)Now, find factors of 12 such that their common factor is only one i.e. find the co-prime factors of 12.

=)Factors of 12 = 1 x 12, 2 x 6, 3 x 4

Here, the only co-prime pair is 3,4

=)Now multiply the numbers by their HCF.

Therefore, 3 x 6 = 18 and 4 x 6 = 24.

=)The two numbers are 18 and 24.

Pomar

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