Math, asked by spandana1657, 3 months ago



18. The length and breadth of a rectangle are in the ratio 1:7. If the perimeter of the
rectangle is 192 m, then find the length of its sides.​

Answers

Answered by kkavinrishi
1

total no of parts =7+1=8

=192/8=24

one part =24

length has 1 part=24

breadth has 7 parts =168

Answered by Anonymous
4

Correct Question-:

  • The length and breadth of a rectangle are in the ratio 1:7. If the perimeter of the rectangle is 192 m, then find the length of its sides.

AnswEr-:

  • \underline{\boxed{\star{\sf{\purple{The\:sides \:of\:Rectangle\:are\:12m,\:84m,\:12m\:and\:84m}}}}}

Explanation -:

Given-:

  • The length and breadth of a rectangle are in the ratio 1:7.
  • The perimeter of the rectangle is 192 m .

To Find -:

  • The length of its side .

Now ,

  • Let the Length and Breadth of the Rectangle be 1x or x and 7x . --------[1]

  • \underline{\boxed{\star{\sf{\blue{ Perimeter_{(Rectangle)}  \: = \: 2(length + breadth)}}}}}

Here ,

  • Length of Rectangle = x m
  • Breadth of Rectangle = 7x m .
  • Perimeter of Rectangle = 192 m

Now ,

  • \implies {\large{\sf{ 192m = 2 ×( x + 7x )  }}}
  • \implies {\large{\sf{ 192m = 2 ×( 8x )  }}}
  • \implies {\large{\sf{ \frac{192}{2} = 8x  }}}
  • \implies {\large{\sf{ 96 = 8x   }}}
  • \implies {\large{\sf{ \frac {96}{8} = x  }}}
  • \implies {\large{\sf{ 12 = x }}}

Therefore,

  • \underline{\boxed{\star{\sf{\blue{ x \: = 12 }}}}}

Now ,

  • Length of Rectangle = x m = 12 m
  • Breadth of Rectangle = 7x m = 84 m

As , we know that ,

  • The parallel sides of Rectangle is equal in length.

Hence ,

  • \underline{\boxed{\star{\sf{\purple{The\:sides \:of\:Rectangle\:are\:12m,\:84m,\:12m\:and\:84m}}}}}

Figure related to this-:

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 12 m}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 84m}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}

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