Question

18
The oscillating electric field of an electromagnetic wave is given by:
2.
E, = 30 sin [2 x 10't +300nx ] Vm!
(a) Obtain the value of the wavelength of the electromagnetic wave.
(b) Write down the expression for the oscillating magnetic field.

Answer 1

Answer:

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Answer 2

Answer:

0.0067m

Explanation:
a)
$E=30sin[2*10^1^1t+300nx]\\ E=E_{0} sin (\omega t + kn)\\k=300\pi \\k=2\pi /\lambda=300\pi \\\lambda= 2/300=1/150\\\lambda=0.0067m$
b)

$E_0/B_0= C\\B_0=E_0/C\\B_0=30/C\\B=B_0 sin (\omega t +kx)$