Question

18. The perimeter of a square field is (4x +8). Find the length of this diagonal.​

Answer 1

The perimeter of the square is (4x +8)...          ( given)

Let consider side of the square =a.

Perimeter will be = 4 ×a   ( as we know that perimeter of a square = 4×side)

∴ 4a = (4x + 8)

a = ( 4x +8) ÷4

a =( x + 2).

Side = (x+2)

now we have to find out the diagonal:-

Diagonal of a square = √2 × side

D=√2 ×a

=> D = √2× (x+2)    

Hence Diagonal of a square  will be$\sqrt{2}$a =$\sqrt{2}$ (x+2).

Ans :- Diagonal will be [ √2 ( x+ 2)] .

Answer 2

Answer:

Diagonal of a square √2 * (x+2) .

Step-by-step explanation:

The perimeter of a square field is (4x +8).

So , we know length of the side of a square is same .

So , length of side = (4x+8)/4 = x+2

Diagonal of a square = √2 * side of square

                                   = √2 * (x+2).

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