Question

18. The value of k for which the pair of linear equations 3kx + 6y = √50 and
√18x+ √24 y=√175 have a unique solution is​

Answer 1

Answer:

The value of k for which the pair of linear equations 3kx + 6y = √50 and√18x+ √24 y=√175 have a unique solution is 6.

Step-by-step explanation:

The particular answer of a linear equation approach that there exists simplest one point, on substituting which, L.H.S and R.H.S of an equation come to be equal.

• The linear equation in a single variable has continually a completely unique answer.
• For example,

3x =6 has a completely unique answer x = 2 for which L.H.S = R.H.S.

$x+2y=5\\ 3x+ky=15 \\ x+2y=5 \\ x=5-2y$

now by putting the value of x in the equation:

$3x + ky = 15$

$3(5-2y)+ky=15 \\15-6y+ky=15 \\ ky-6y=15-15 \\ y(k-6)=0 \\ k=6$

(#SPJ3)

Answer 2

Answer:

Concept :

A linear equation is an algebraic equation wherein each time period has an exponent of one and whilst this equation is graphed, it always consequences in an immediate line. This is the reason why it is known as as a 'linear equation'. There are linear equations in one variable and linear equations in two variables.

Step-by-step explanation:

Given :

3kx  + 6y = 50

√18x + √24y  = $\sqrt{175}$

To find :

k

Solution :

Dividing the equation we get,

x+2y=5

3x+ky=15

•°•x=5-2y

3x+ky=15

3(5-2y)+ky=15

15-6y+ky=15

ky-6y=15-15

y(k-6)=0

k-6=0

k=6

#SPJ3