18.Three resistors 5 ohm ,10 ohm , 30
ohm are connected in parallel with 12 V
battery. Calculate
a. Current through each resistor
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Answer:
2.4 A , 1.2 A & 0.4 A are the current through each resistor..
Explanation:
given:-
-R1 = 5 ohm
-R2 = 10 ohm
-R3 = 30 ohm
-(potential difference) V = 12 V
as given resistances are connected in parallel , so current will be different and potential difference remains same...
According to ohm's law:-
V= IR
I=V÷R
let the I1 ,I2 and I3 are the current flowing through these resistance.
so, I1 = V÷R1 = 12÷5 = 2.4 A
I2= V÷R2 = 12÷10 = 1.2 A
I3 = V÷R3 = 12÷30 = 0.4 A
hence , 2.4 A , 1.2 A & 0.4 A are the current through each resistor..
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