Question

18. To find prominent diffraction , the size of diffraction object should be
(A) Greater than wavelength of light used
(B) Comparable to order of wavelength of light
(C) Less than wavelength of light used
(D) None of these​

Answer 1

Answer:

(B) Comparable to order of wavelength of light

Explanation:

To observed diffraction, the size of the obstacle should be of the order of wavelength. i.e. λ=d.

(This is the correct one)

Answer 2

" Option B) Comparable to order of wavelength of light ".

Explanation:

Diffraction is basically the bending of waves. The bending occurs due to the obstacles. It happens only when the wavelength is comparable to the size of aperture. As the wavelength (λ) increases, the diffraction (a) effect will also increase.

For this the greater diffraction, it is important that the size of the obstacle is directly proportional to the wavelength of the source. Consider diffraction is a and λ is the wavelength. Therefore for diffraction, size of obstacle should be in the order of a wavelength.

To observed diffraction, the size of the obstacle should be of the order of wavelength. that is λ=d.

To notice diffraction of light the size of obstacle or aperture should be of the order of 10 to 7m. 10-7m is the order of wavelength of visible light.

So, To find prominent diffraction , the size of diffraction object should be comparable to order of wavelength of light.