Question

18. Two dices are thrown together. What is the
probability of getting a total of at least 6? ​

Answer 1

Answer:

Let E2 be the event of getting the sum 6. Then,

E2 = {(1, 5), (2, 4), (3, 3), (4, 2), (5, 1)}

⇒ P(E2) = 5

Therefore, P(E2) = n(E2)/n(S) = 5/36

⇒ odds against E2 = [1 – P(E2)]/P(E2) = (1 – 5/36)/(5/36) = 31/5.

Answer 2

Answer:

given: two dices are thrown at the same time means each dice having up to 6 digits so two dices means total chances are double for each digit so 6/12= 1/2