Question

(18) Two trains A and B, 100 km apart are approaching towards each ole
with starting speed of 50 km/hr ^2for both. The train A is accelerating at 11
km/hr". The distance where the engines cross each other from starting pe
of A is
a. 32 km
c. 59 km
b. 50 km
d. 68 km​

Answer 1

Answer:

68

Explanation:

ssume train A is behind (by 100km)

And train B is ahead.

Let A and B meet after time 't' = s;

Displacement of train A after the same time would be = s +100;

s=50t−  

2

1

​  

20t  

2

=50t−10t  

2

 

and

s+100=50t+10t  

2

 

i.e.

50t+10t  

2

−100=50t−10t  

2

 

i.e.

20t  

2

=100

t=  

5

​  

 

Distance travelled by A = s+100=50(  

5

​  

)+10(5)=161.80km

Answer 2

Explanation:

Answer:

68

Explanation:

ssume train A is behind (by 100km)

And train B is ahead.

Let A and B meet after time 't' = s;

Displacement of train A after the same time would be = s +100;

s=50t−  

2

1

 

20t  

2

=50t−10t  

2

 

and

s+100=50t+10t  

2

 

i.e.

50t+10t  

2

−100=50t−10t  

2

 

i.e.

20t  

2

=100

t=  

5

 

 

Distance travelled by A = s+100=50(  

5

 

)+10(5)=161.80km

hope it helps ☺️☺️☺️