Question

18 value of a quadratic polynomial p(x) is 0 only at x=-1 and p(-2)= 2, then value of p(3) is:

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Answer 1

Answer:

There are some given hints to this question.

it is a quadratic polynomial in x, so its degree is 2

also it is 0 only in x= -1

so x+1 is a factor and hence its degree 2 again x+1 is factor

so (x+1)^2 is a factor

now as p(-2)=2, so let us put -2 in (x+1)^2 we get 1, but we need 2 as answer

so multiply with 2 and the polynomial becomes 2{(x+1)^2}

so now to find p(2)

putting the value in p(x) = 2{(x+1)^2}

we get p(2) = 18

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Answer 2

Answer:

Step by Step Explanation:

Correct option is C) 6

Equation is 0 at x=−1

》(x+1) is a factor

Quadratic is (x+α)(x+1=0)

 p(−2)=2

(-2+α)(−2+1)=2

2-a=2

a=0

Polynomial is 

x²+x=0

》2²+2=4+2=6

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