18. Verify 576 is divisible by 2.3.6 and 9?
19. Write all the numbers between 100 and 200 which are divisible by 6?
20. Find the value of
3 1 1
4 3 4
21. The product of two numbers is 25. If one of the number is oz. then find the
22. The length of a rectangular field is 12 - mts and its area is 65*
Find its br
2
Answers
Answer:
subject plz mark me briliest answer
Answer:
18. 6
19. First no. between 100 and 200 that is divisible by 6 is 102
The last no. between 100 and 200 that is divisible by 6 is 198
Now the numbers between 100 and 200 that is divisible by 6:
102,102+6,102+6+6 ,....
So, it forma an AP
a = first term = 102
d = common difference = 6
a_n=198a
n
=198
Formula of nth term = a_n=a+(n-1)da
n
=a+(n−1)d
198=102+(n-1)6198=102+(n−1)6
198-102=(n-1)6198−102=(n−1)6
96=(n-1)696=(n−1)6
\frac{96}{6}=n-1
6
96
=n−1
16=n-116=n−1
17=n17=n
Sum of n terms = s_n=\frac{n}{2}(2a+(n-1)d)s
n
=
2
n
(2a+(n−1)d)
Substitute n =17
s_{17}=\frac{17}{2}(2(102)+(17-1)6)s
17
=
2
17
(2(102)+(17−1)6)
s_{17}=2550s
17
=2550
Hence the sum of integers between 100 and 200 that are divisible by 6 is 2550