18. What is the molality of a solution which contains
18 g of glucose (C6H1206) in 250 g of water?
a) 14.0 m
b) 0.4 m
c) 4.2 m
d) 0.8 m
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- Given that,
- Mass of solute, w =18g
- Mass of solute, W =250g
- Now,
- Molality, m=
- M×W
- w
- ×1000=
- 180×250
- 18×1000
- =0.4m
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