Question

18. When Xe and F, in 1:20 ratio is heated at 400°C in a sealed nickel vessel it form?​

Answer 1

Answer:

◆ Answer - XeF4

◆ Extra information-

Heating Xe and F2 in sealed nickel container at 400 °C will give different compounds based on proportion of reactants-

- Xe:F2 = 2:1 will give XeF2 as product

- Xe:F2 = 1:5 will give XeF4 as product

- Xe:F2 = 1:20 will give XeF6 as product

Answer 2

Answer:

Xenon hexafluoride(XeF₆) forms when Xe and F are taken in a 1:20 ratio heated at 400°C.

Explanation:

The reaction will proceed as follows,

$Xe(g)+3F_2(g)\rightarrow XeF_6(s)$        (1)

Where,

Xe=xenon

F₂=fluorine gas

XeF₆=xenon hexafluoride

The reaction of Xe and F, in a 1:20 ratio, is heated at 400°C in a sealed nickel vessel resulting in the formation of xenon hexafluoride.

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