Question

18 x square A square - 32

Solve this factor...

Answer 1

18x²a² - 32

2( 9x²a² - 16 )

2{ ( 3xa )² - 4² }




By using formula, a² - b² = ( a + b ) ( a - b )



2( 3xa + 4 ) ( 3xa - 4 )





Hence, 18x²a² - 32 = 2( 3xa + 4 )( 3xa - 4 )
$.$

Answer 2

Hey there!

Given to factorize : 18x²a² - 32

=> 18a²x² - 32

=> 2 ( 9a²x² - 16 )

=> 2 [ ( 3ax)² - 4² ]

= 2( 3ax+4) ( 3ax-4)

Formulae used : a² - b² = ( a + b) ( a - b)

The zeroes of the polynomial :

( 3ax + 4 ) (3ax - 4 ) = 0

3ax + 4 = 0 or 3ax - 4 = 0

3ax = -4 or 3ax = 4
$x = \frac{ - 4}{3a} \: \: or \: \frac{4}{3a}$

Hope helped!