Question

18. यदि x2+1/x2=51
है, तो x+ 1/x का मान ज्ञात कीजिए।​

Answer 1

Answer:

$\left(x+\frac{1}{x}\right)=±\sqrt{53}$

Step-by-step explanation:

$Given \: x^{2}+\frac{1}{x^{2}}=51$

$\implies x^{2}+\frac{1}{x^{2}}+2=51+ 2$

$\implies x^{2}+\frac{1}{x^{2}}+2\times x \times \frac{1}{x}=53$

$\implies \left(x+\frac{1}{x}\right)^{2}=53$

$\implies \left(x+\frac{1}{x}\right)=±\sqrt{53}$

Therefore,

$\left(x+\frac{1}{x}\right)=±\sqrt{53}$

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Answer 2

Answer:(√53)

Step-by-step explanation:

Given, x^2+(1/x)^2=51

To find:x+(1/x)=?

Now, x^2+(1/x)^2=51

Or, (x)^2+2*x*(1/x)+(1/x)^2 -2=51

Or, {x+(1/x)}^2=51+2

Or, {x+(1/x)}^2=53

Therefore x+(1/x)=(√53)