Question

18 year ago the ratios of age of A age to B age is 8:13 their present ratio are5:7what is the present age of A​

Answer 1

$\huge\bold\red{\underline{Solution:}}$

$\large{\underline{\purple{\rm{Let:}}}}$

• The ratio of A and B be X
• The present age of A be 5X
• The present age of B be 7X

$\large{\underline{\green{\rm{To\: Find:}}}}$

• The present age of A and B

$\large{\underline{\red{\rm{As\:per\:the\: Question:}}}}$

18 year's ago the ratio of ages of A and B age is 8:13

$\implies \frac{5x-18}{7x-18}=\frac{8}{13}\\\\ \implies 65x-234=56x-144\\ \\ \implies 65x-56x=-144+234\\ \\ \implies\cancel{9}x=\cancel{90}\\ \\ \implies x=10$

Hence,

The present age of A=5×10=50year's

The present age of B=7×10=70year's

$\large{\underline{\red{\rm{AnswEr:}}}}$

$\large{\boxed{\orange{\rm{A's\:age=50\: year's:}}}}$

$\large{\boxed{\purple{\rm{B's\:age=70\: year's:}}}}$