Question

18 years ago, father was 3 times as old as his son. Now father is tauce old ay his son. what is the sum of their present aces?​

Answer 1

Answer:

• The sum of their ages is 108yrs.

Step-by-step explanation:

Given,

• 18 years ago, father was 3 times as old as his son.
• Now, father is twice old as his son.

To Find,

• The sum of their present ages.

Solution,

Let's,

• The present age of son = x

So,

• The present age of father = 2x

Before 18 years,

• The age of son = x - 18
• The age of father = 2x - 18

According to Question,

• The age of father = 3(The age of son)
• → 2x - 18 = 3(x - 18)
• → 2x - 18 = 3x - 54
• → 54 - 18 = 3x - 2x
• → x = 36

The present age of son = x

• The present age of son = 36yrs

The present age of father = 2x

• The present age of father = 72yrs

The sum of their ages = 36yrs + 72yrs

• The sum of their ages = 108yrs

Required Answer,

• The sum of their ages is 108yrs.