Question

18 years ago the father's age is 9 times older than his son. Now , father is 3 times older than his son. Find their present ages?​

Answer 1

✪ Question ✪

18 years ago the father's age is 9 times older than his son. Now, father is 3 times older than his son. Find their present ages?

✪ Given ✪

18 years ago the father's age is 9 times older than his son. Now, father is 3 times older than his son.

✪ To find ✪

Their present ages.

✪ Solution ✪

Let son's present age be x yrs.

So, father's present age = 3x yrs.

18 years ago,

• son's age = (x-18) yrs
• father's age = (3x-18) yrs

According to condition,

(3x-18) = 9(x-18)

↝ 3x-18 = 9x-162

↝ 3x-9x = -162+18

↝ -6x = -144

↝ 6x = 144

↝ x = 144/6

↝ x = 24

✪ Hence ✪

x = 24

So, son's age = x yrs = 24 yrs

And father's age = 3x yrs = (2×24) yrs = 72 yrs

✪ Therefore ✪

Their present ages are 24 years and 72 years respectively.

-------------------------------------------------------------

✪ Verification ✪

(3x-18) = 9(x-18)

↝(72-18) = 9(24-18)

↝54 = 216-162

↝54 = 54

So, L.H.S = R.H.S.

Hence, verified.

๑ Hope this helps you. ๑