Question

180 cm of a hydrocarbon diffuses in 15 min, while under the same conditions. 120 cm of SO, diffuse in 20 min. If the molecular weight of SO, is 64, what is the molecular formula of the hydrocarbon?​

Answer 1

Answer:

r

1

= rate of diffusion of hydrocarbon =

15

180

mL min

−1

r

2

= rate of diffusion of SO

2

=

20

120

mL min

−1

r

2

r

1

=

M

M

SO

2

Thus,

120/20

180 15

=

M

64

2=

M

64

So, M=16