180 cm, what will be the area of the signal board
The triangular side walls of a flyover have been used for advertisement. The
the walls are 122 m, 22 m and 120 m (see Fig. 12.9) The advertisements
earning of 5000 per m per year
. A company hired one of is walle for
much rent did it pay?
Answers
Answer:
Question ✌1
180 cm, what will be the area of the signal board
The triangular side walls of a flyover have been used for advertisement. The walls are 122 m, 22 m and 120 m. The advertisements earning of 5000 per m per year. A company hired one of is wall for much rent did it pay?
The rent paid by the company for 3 months is ₹ 1650000. Ans.
Given that:
The side walls of a flyover which have been used for advertisements are triangular in shape.The length of Wall are 122m,22m and 120m.
As (122)² = 14884 = (122)² + (120)²
i.e. , By Pythagoras theorem, the walls in the shape of right triangles.
The advertisements yield an earning of ₹5000 per m² per year.
A company hired bone of its walls for 3 months.
To find:
How much did the rent paid by the company for 3 months?
Before solving question we must to know this formula:-
The perimeter of a triangle is equal to the sum of its three sides it is denoted by 2S.
2s=(a+b+c)
s=(a+b+c)/2
Here ,s is called semi perimeter of a triangle.
The formula given by Heron about the area of a triangle is known as Heron's formula.
According to this formula area of a triangle= √s (s-a) (s-b) (s-c)
Where a, b and c are three sides of a triangle and s is a semi perimeter.
This formula can be used for any triangle to calculate its area and it is very useful when it is not possible to find the height of the triangle easily .
Heron's formula is generally used for calculating area of scalene triangle.
___________________________
Solution:
Let the sides of the triangle are a=122 m, b=22 m & c= 120 m.
Semi Perimeter of the ∆,s = (a+b+c) /2
s=(122 + 22 + 120) / 2
s= 264/2= 132m
Using heron’s formula,
Area of the wall = √s (s-a) (s-b) (s-c)
= √132(132 – 122) (132 – 22) (132 – 120)
= √132 × 10 × 110 × 12
=√11×12×10×11×10×12
=√11×11×12×12×10×10
= 11×12×10
= 1320m²
Given, earning on 1m² per year= ₹5000
Earning on 1320 m² per year=1320×5000= ₹6600000
Now, earning in 1320 m² in 12 months= ₹6600000
earning in 3 months = ₹ 6600000 ×3/12 = ₹ 1650000
- Hence, the rent paid by the company for 3 months is ₹ 1650000.
__________________________
The rent paid by the company for 3 months is ₹ 1650000 . (Ans) .
Given that :
The side walls of a flyover which have been used for advertisements are triangular in shape.The length of Wall are 122m,22m and 120m.
As (122)² = 14884 = (122)² + (120)²
i.e. , By Pythagoras theorem, the walls in the shape of right triangles.
The advertisements yield an earning of ₹5000 per m² per year.
A company hired bone of its walls for 3 months.
To find:
How much did the rent paid by the company for 3 months?
Before solving question we must to know this formula:-
The perimeter of a triangle is equal to the sum of its three sides it is denoted by 2S.
2s = (a+b+c)
s = (a+b+c)/2
Here , s is called semi perimeter of a triangle.
The formula given by Heron about the area of a triangle is known as Heron's formula.
According to this formula area of a triangle = √s (s - a) (s - b) (s - c)
Where a, b and c are three sides of a triangle and s is a semi perimeter.
This formula can be used for any triangle to calculate its area and it is very useful when it is not possible to find the height of the triangle easily .
Heron's formula is generally used for calculating area of scalene triangle.
___________________________
Solution:
Let the sides of the triangle are a = 122 m, b = 22 m & c = 120 m.
Semi Perimeter of the ∆ , s = (a+b+c) /2
s = (122 + 22 + 120) / 2
s = 264/2
= 132m
Using heron’s formula,
Area of the wall = √s (s-a) (s-b) (s-c)
= √132(132 – 122) (132 – 22) (132 – 120)
= √132 × 10 × 110 × 12
= √11×12×10×11×10×12
= √11×11×12×12×10×10
= 11×12×10
= 1320m²
Given, earning on 1m² per year = ₹5000
Earning on 1320 m² per year = 1320 × 5000 = ₹6600000
Now, earning in 1320 m² in 12 months = ₹6600000
earning in 3 months = ₹ 6600000 ×3/12 = ₹ 1650000
Hence, the rent paid by the company for 3 months is ₹ 1650000.