180 ml of pure water at 4∘C
is saturated with NH3
gas, yielding a solution of density 0.8 gram/ml and containing NH3
(40% by weight ).
(a) Volume of NH3
solution.
(b) Volume of NH3
gas present in saturated solution.
(c ) Volume of NH3
gas at 115^(@)C` and 950 mm of Hg in saturated solution.
Answers
Answered by
1
Answer:
Solution has 30% NH
3
by mass.
Therefore, 100 g solution has 30 g NH
3
dissolved in it.
or 70 g H
2
O is saturated by NH
3
= 30 g
∴ 105 g H
2
O will be saturated by NH
3
=
70
30×105
=45 g NH
3
∴ Mass of saturated solution = 100+45 = 150 g
Volume of saturated solution =
density
150
=
0.9
150
=166.67 mL
Now, volume of NH
3
(45 g) at 4
o
and 775 mm pressure,
PV=
m
w
RT
⟹
760
775
×V=
17
45
×0.0821×277
⟹ V=59.03=59 L
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