Question

1800 boys and 900 girls appeared for an examination. If 42% of the boys and 30% of
the girls passed, find
() number of boys passed
1. (i) number of girls passed
(iii) total number of students passed (iv) number of students failed
(v) percentage of students failed.​

Answer 1

Answer:

1. Number of boys passed =

$42\% \: of \: 1800 \\ = \frac{42}{100} \times 1800 \\ = 42 \times 18 \\ = 756$

2. Number of girls passed =

$30\% \: of \: 900 \\ = \frac{30}{100} \times 900 \\ = 270$

3. Total number of students passed =

$756 + 270 \\ = 1026$

4. Number of students failed =

$2700 - 1026 \\ = 1674$

5. Percentage of students failed =

$\frac{1674}{2700} \times 100\% \\ = \frac{1674}{27} \% \\ = 62\%$

Answer 2

$\huge\mathbf\blue{Question}$

1800 boys and 900 girls appeared for an examination. If 42% of the boys and 30% of

the girls passed, find

(i) number of boys passed

(ii) number of girls passed

(iii) total number of students passed

(iv) number of students failed

(v) percentage of students failed.

$\huge\mathfrak\purple{Required \: Answer}$

$\mathit\blue{Given \: ,}$

Students appeared for examination :

$\mathbf\red{Boys \: =\:1800 \: , \: Girls \: = \: 900}$

(I) Number of boys passed =

$\begin{gathered}42\% \: of \: 1800 \\ = \frac{42}{100} \times 1800 \\ = 42 \times 18 \\ = 756\end{gathered}$

$\mathbf\green{1 \: = 756}$

(ii) Number of girls passed =

$\begin{gathered}30\% \: of \: 900 \\ = \frac{30}{100} \times 900 \\ = 270\end{gathered}$

$\mathtt\blue{2\:=\:270}$

(iii) Total number of students passed =

$\begin{gathered}756 + 270 \\ = 1026\end{gathered}$

$\mathbf\orange{3 \: =\: 1026}$

(iv) Number of students failed =

$\begin{gathered}2700 - 1026 \\ = 1674\end{gathered}$

$\mathbb\pink{4\:=\:1674}$

(v) Percentage of students failed =

$\begin{gathered} \frac{1674}{2700} \times 100\% \\ = \frac{1674}{27} \% \\ = 62\%\end{gathered}$

$\mathbb\red{5\:=\: 62}$

$\mathbf\orange{Hope\: it's\: helpful\: for \:you}$