Question

1800 pe 10% rate par compound intrest 378 ₹ h to what is time perioud??

Answer 1

HEY Buddy......!! here is ur answer

Given that... P = 1800 Rs. , R = 10% and
C.I. = 378 Rs.

we know that.....

$c.i. = p[ ({1 + \frac{r}{100}) }^{t} - 1] \\ \\ = > 378 = 1800[( {1 + \frac{10}{100}) }^{t} - 1] \\ \\ = > \frac{378}{1800} = ( { \frac{110}{100} )}^{t} - 1 \\ \\ = > \frac{21}{100} = ({ \frac{110}{100} )}^{t} - 1 \\ \\ = > \frac{21}{100} + 1 = ({ \frac{110}{100}) }^{t} \\ \\ = > \frac{121}{100} = ( { \frac{11}{10} )}^{t} \\ \\ = >( { \frac{11}{10}) }^{2} = ({ \frac{11}{10}) }^{t} \\ \\ = > t = 2$

Therefore, the time period = t = 2 years

I hope it will be helpful for you...!!

THANK YOU ✌️✌️

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