Question

1800 people attended the national Day Dinner in a certain constituency. Given that 35.5% of them were men, 40% of them were women and the rest were children,find the number of children who attended the dinner Please answer Who ever answers best I will mark as brainliest

Answer 1

Hope this answer will help you

Answer 2

Step-by-step explanation:

$\bf{\underline{\underline\red{Given:-}}}$

• 1800 people attended the National Day Dinner .

• 35.5% of them were men

• 40% of them were women

• And the rest of them were children.

$\bf{\underline{\underlin ofe\blue{To\:Find:-}}}$

• The number of children attended the dinner.

$\bf{\underline{\underline\green{Solution:-}}}$

Total number of people attended = 1800

Percentage of men = 35.5%

Number of men = 35.5% of 1800

$= \dfrac{35}{100} \times 1800$

$= 35 \times 18$

= 630

Percentage of women = 40%

Number of women

$= \dfrac{40}{100} \times 1800$

$= 40 \times 18$

= 720

Number of children

= Total number of people - (Number of men + Number of women)

= 1800 - (630 + 720)

= 1800 - 1350

= 450

Therefore:-

Total number of children = 450

$\large\bf{\underline{\underline\purple{Alternatively:-}}}$

Percentage of men = 35.5%

Percentage of women = 40%

Percentage of children

= 100 - ( 35 + 40)

= 100 - 75

= 25%

Number of children

= 25% of 1800

$= \dfrac{25}{100} \times 1800$

= 25 × 18

= 450

$\boxed{ \rm \therefore Number \: of \: students \: = 450}$