Math, asked by biswarajan84, 4 months ago

18000(100+R)^2-10000-200R)÷10000​

Answers

Answered by bombboy
1

Answer:

225

Step-by-step explanation:

Let the rate be R% p.a.

[ 18000 ( 1 + ( R / 100 )^2 ) - 18000 ] - ((18000 * R * 2) / 100 ) = 405

18000 [ ( 100 + (R / 100 )^2 / 10000) - 1 - (2R / 100 ) ] = 405

18000[( (100 + R )^ 2 - 10000 - 200R) / 10000 ] = 405

9R^2 / 5 = 405

R^2 =((405 * 5 ) / 9) = 225

R = 15.

Rate = 15%.

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