Question

₹18000 for 3 year at 12 1/2 %
per annum compounded ​

Answer 1

Answer:

p=18000

t=3 year

r= 121/2%

si= p×r×t/100

answer =675

Answer 2

Answer:

₹ 25627.90

Step-by-step explanation:

Principal = ₹18,000

Rare of Interest(R)=$12\frac{1}{2}$% = $\frac{25}{2}$%

Time (T)= 3 yrs

$C.I.=[P(1+\frac{R}{100})-1]$

$C.I=[18,000(1- \frac{25}{2*100} )^{3} -1]$

$C.I.=[18000(\frac{9}{8})^{3}-1]$

$C.I.=2250*\frac{729}{64}$

$C.I =\frac{1640250}{64} -1$

$C.I=\frac{1640250-64}{64}$

$C.I.=\frac{1640186}{64}$

C.I. = ₹25627.90