Question

180g of glucose is added to 1000g of water, forming
a solution of density 1.18g/ml. Molarity of glucose
solution is ?
(1) 1.2 M
(2) 2.0 M
(3) 1.8 M
(4) 1 M​

Answer 1

Answer:

4. will be correct answers

Answer 2

answer : option (d) 1M

mass of glucose = 180 g

molar mass of glucose, (C6H12O6) = 12 × 6 + 12 × 1 + 16 × 6 = 72 + 12 + 96 = 84 + 96 = 180g/mol

so no of mole of glucose = 180/180g/mol = 1 mol

mass of water = 1000g

mass of solution = 1000 + 180 = 1180g

volume of solution = 1180/1.18 = 1000 ml

now molarity of glucose = no of mole of solute/ volume of solution in L

= 1/(1000/1000)

= 1 M

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