Question

180ml of water is added to NaOH to prepare 12 percent of solution. Find the amount of base taken​

Answer 1

Answer:The molarity of a solution (or, more precisely, of a solute in a solution) is the number of moles

of the solute in 1 litre of the solution.

molarity = M = N.B.: n = moles (solute)

litres (solution)

n

V(L)

mass (g)

MM

(MM = molar mass ≡ MW or FW)

The equation can also be used to find n (the number of moles of solute) if M (the molarity) and

V (the volume in litres) are known, and V if n and M are known.

n = MV V =

n

M

-4

Explanation:

Answer 2

Answer:

NaOH solution is prepared in water.

Molar mass of NaOH=40 g

Mass of NaOH=10 g

Molar mass of water = 18 g

Given mass of water = 90 g

Number of moles of NaOH=

40

10

=0.25 moles

Number of moles of H

2

O=

18

90

=5 moles

Mole fraction of NaOH=

0.25+5

0.25

=0.047