182-130÷10+5of 3(1÷2+3÷2) solve by bodmas method
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Answered by
4
Bodmas:
we have to solve first brackets i.e (1/2 plus3/2) equals to 2. so 3(2)equals to 6.
division 130/10 equals to 13.
multipication 6 i.e 3(2)
addition 13 plus 30 equals to 43
subraction 182-43
so we got .
by solving we get 199
we have to solve first brackets i.e (1/2 plus3/2) equals to 2. so 3(2)equals to 6.
division 130/10 equals to 13.
multipication 6 i.e 3(2)
addition 13 plus 30 equals to 43
subraction 182-43
so we got .
by solving we get 199
Anonymous:
199 comes
182-18=164
uske baad
solve that by back....
it is easy to find
subraction ,addition..... like this
thank you
how can you subtract 18 , only 13 can be subtracted??
i thought there 13+5 soo
now its clear
Answered by
6
first solving bracket (1/2 + 3/2)
= (4/2) = 2
then of
5of 3 (2)
=5*3*2
= 15*2
=30
then division
130 ÷ 10
= 13
then addition and subtract
182 - 13 + 30
= 212 - 13
= 199
= (4/2) = 2
then of
5of 3 (2)
=5*3*2
= 15*2
=30
then division
130 ÷ 10
= 13
then addition and subtract
182 - 13 + 30
= 212 - 13
= 199
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