Question

183. An elevator is accelerating upward at a rate of
6 ft/sec2 when a bolt from its ceiling falls to the
floor of the lift (Distance = 9.5 feet). The time
(in seconds) taken by the falling bolt to hit the floor
is (take g = 32 ft/ sec?).
(1)√2
(2)1/√2
(3)2√2
(4)1/2√2​

Answer 1

Answer:

0.8549 sec

Explanation:

$9.5 = \frac{1}{2} \times 26 t {}^{2} \\ t = \sqrt{ \frac{(2 \times 9.5)}{26} } sec \\ t = \sqrt{ \frac{19}{26} } sec \\ t = 0.8549sec$

We know

$s = ut + \frac{1}{2} at {}^{2}$

S=9.5ft

a=(32-6)=26ft/sec^2

Now, initially. u=0

So,