Question

184g ethyl alcohol is mixed with 72g of water. the ratio of mole fraction of alcohol to water

Answer 1

Answer:

The answer is question on when when you simplify it

Explanation:

But at that point of time the answer is 184ratio 72

Answer 2

Answer: 1:1

Explanation:

Molar mass of ethyl alcohol()=(12*6)+(1*6)+(16*1)

                                                               =24+6+16 =46g

Molar mass of $H_{2}O$= 2+16 =18g

No. of moles of $C_{2}H_{6}O$ =$\frac{184}{46}$  = 4M

No. of moles of water= $\frac{72}{18 }$ = 4M

Mole fraction of ethyl alcohol= $\frac{(No. of moles of ethyl alcohol)}{(No. of moles of ethyl alcohol + No. of moles of water)}$

                                                   = $\frac{4}{4+4}$ = $\frac{1}{2}$

Mole fraction of water= $\frac{(No. of moles of water)}{(No. of moles of ethyl alcohol + No. of moles of water)}$

                                                  = $\frac{4}{4+4}$ = $\frac{1}{2}$

Mole fraction of ethyl alcohol : Mole fraction of water = $\frac{(1/2)}{(1/2)}$

                                                                                             = $\frac{1}{1}$

                                                                                             = 1:1