Question

185 sheep, 111 cows, and 296 goats are to be taken across a river. There is only
one boat and the boatsman says, he will take the same number and same kind of
animals on each trip. Find the largest number of animals on each trip and the
number of trips he will have to make.

Answer 1

Answer:

16 is the answer.

Step-by-step explanation:

To calculate the highest number which can divide all these three numbers, we will have to find their  HCF .  

the factors of 185 are - 5 and 37

of 111 are -- 3 and 37  

and of 296 are -- 2 ,2,2 and 37  

so, the hcf is 37.  

therefore, maximum 37 animals can be taken in the boat at a time.  

total no. of animals = 185+111+296 = 592  

so, no. of trips = 592 divided by 37 = 16